2x(x^4-81)(x+1)=0

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Solution for 2x(x^4-81)(x+1)=0 equation: 


Simplifying
2x(x4 + -81)(x + 1) = 0

Reorder the terms:
2x(-81 + x4)(x + 1) = 0

Reorder the terms:
2x(-81 + x4)(1 + x) = 0

Multiply (-81 + x4) * (1 + x)
2x(-81(1 + x) + x4(1 + x)) = 0
2x((1 * -81 + x * -81) + x4(1 + x)) = 0
2x((-81 + -81x) + x4(1 + x)) = 0
2x(-81 + -81x + (1 * x4 + x * x4)) = 0
2x(-81 + -81x + (1x4 + x5)) = 0
2x(-81 + -81x + 1x4 + x5) = 0
(-81 * 2x + -81x * 2x + 1x4 * 2x + x5 * 2x) = 0
(-162x + -162x2 + 2x5 + 2x6) = 0

Solving
-162x + -162x2 + 2x5 + 2x6 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2x'.
2x(-81 + -81x + x4 + x5) = 0

Ignore the factor 2.

Subproblem 1
Set the factor 'x' equal to zero and attempt to solve:

Simplifying
x = 0

Solving
x = 0

Move all terms containing x to the left, all other terms to the right.

Simplifying
x = 0

Subproblem 2
Set the factor '(-81 + -81x + x4 + x5)' equal to zero and attempt to solve:

Simplifying
-81 + -81x + x4 + x5 = 0

Solving
-81 + -81x + x4 + x5 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.
Solution
x = {0}

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